simplify the trigonometric expression *problem below*
\[ \frac{ \sin x }{ \cos x }+\frac{ \cos x }{ \sin x}\]
just add the fractions.
That's like adding\[{x \over y} + {y\over x}\]
\[ {\sin^2 x + \cos^2 x \over\sin x \cos x} \]
Note that the numerator is 1.
when i worked it out on a web calculator it gave me the answer tan(x) + cos(x) but i knew it was wrong because the answer was multiple choice
my only choices are a. (sec x)(csc x) b. 1 c 2(sin x)(cos x)/sin^2x + cos^2x
Since\[2\sin(x)\cos(x) = {\sin(2x)}\]we may say\[\sin(x)\cos(x) = 0.5\sin(2x)\]
We already have,\[{1 \over 0.5\sin(2x)} \implies 2\sin(2x) \implies 4\sin(x)\cos(x)\]
but which one of those answers does that come out to. im not sure how to get from that to one of my choices
@ParthKohli - you showed the first step correctly, i.e.:\[\frac{\sin x}{\cos x}+\frac{\cos x}{\sin x}={\sin^2 x + \cos^2 x \over\sin x \cos x}=\frac{1}{\sin x\cos x}\]
I found a mistake.
the next step is to notice that:\[\frac{1}{\sin x}=cosec x\]and:\[\frac{1}{\cos x}=sec x\]
yes. those are the only options given with the question being "which of the following is the correct simplification of the trigonometric expression?"
I made a very elementary mistake...
Ironically, I was doing the SAME question earlier this day and I did it correctly!
:)
lol. its ok we all make mistakes sometimes.
@kizzfan911 you should now be able to work out the correct answer from the information given to you.
ok. ill see what i can do.
hint:\[\frac{1}{\sin x\cos x}=\frac{1}{\sin x}\times\frac{1}{\cos x}\]
i ended up getting sec(x)/sin(x)
use the two clues I gave above regarding what 1/sin x equals, and what 1/cos x equals
cosec(x) is the same as csc(x)
0h ok. so its (sec x)(csc x)? i was entering it into the calculator wrong
yes :)
thank you. your help is much appreciated.
yw :)
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