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Find the vertical asymptote of f(x)=tan2x
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\[\tan^2(x)\]or\[\tan(2x)\]?
tan(2x)
Right. The vertical asymptote is just a value of \(x\) which makes \(f(x)\) undefined. Do you follow?
Yes
We also know that \(\tan(\alpha)\) is undefined at \(\alpha = \large{\pi \over 2}\)
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So, if the vertical asymptote is at \(\tan({\pi \over 2})\), and also at \(\tan(2x)\), then what is x = ?
Do we set that equal to 0 to solve for x?
tan (pi/2) = tan (2x) what do we get if we cross out the tan's?
2x= pi/2 ?
exactly - so solve that for x and u have your answer
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thank you!
yw
Yeah
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