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Mathematics 8 Online
OpenStudy (anonymous):

Factor 6y^2+11y+4

OpenStudy (anonymous):

(2y+3)(3y+4)

OpenStudy (zzr0ck3r):

@aceace this is not right, and please don not just give answers, even if they are right. read rules.

OpenStudy (anonymous):

sorry my bad

OpenStudy (anonymous):

8 and 9 doesn't equal 11..

OpenStudy (zzr0ck3r):

we want to things that multiply to = 6*4 but add to equal 11 two such numbers are 8 and 3 so expant the middle term 6y^2 +3y+8y+4 note: I put the 3 on the left so that it would factor out nicely.

OpenStudy (zzr0ck3r):

can you do the rest @Mberdeja501 ?

OpenStudy (zzr0ck3r):

expant = expand

OpenStudy (anonymous):

replace te constant 3 with 1

OpenStudy (zzr0ck3r):

again, please do not just give answers...we just went over this.

OpenStudy (anonymous):

jsut clearing up my mistake

OpenStudy (anonymous):

so then 6y^2+3y+8y+4 factors out to y(6y+3)+2(6y+2)? @zzr0ck3r

OpenStudy (zzr0ck3r):

no factor out a 3y from the first 2 terms and a 4 from the last 2 and tell me what you get

OpenStudy (anonymous):

ohhh ok i see! so i get 3y(2y)+4(2y)

OpenStudy (zzr0ck3r):

lets jsut look at the first two terms 6y^2+3y factor out a 3y (devide both terms by 3y) 3y(2y+1))

OpenStudy (anonymous):

yeah i was wondering where do i get the +1 from. but now i get it completely! Thank you @zzr0ck3r!

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