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OpenStudy (anonymous):
(2y+3)(3y+4)
OpenStudy (zzr0ck3r):
@aceace this is not right, and please don not just give answers, even if they are right. read rules.
OpenStudy (anonymous):
sorry my bad
OpenStudy (anonymous):
8 and 9 doesn't equal 11..
OpenStudy (zzr0ck3r):
we want to things that multiply to = 6*4 but add to equal 11
two such numbers are 8 and 3
so expant the middle term
6y^2 +3y+8y+4
note: I put the 3 on the left so that it would factor out nicely.
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OpenStudy (zzr0ck3r):
can you do the rest @Mberdeja501 ?
OpenStudy (zzr0ck3r):
expant = expand
OpenStudy (anonymous):
replace te constant 3 with 1
OpenStudy (zzr0ck3r):
again, please do not just give answers...we just went over this.
OpenStudy (anonymous):
jsut clearing up my mistake
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OpenStudy (anonymous):
so then 6y^2+3y+8y+4 factors out to y(6y+3)+2(6y+2)? @zzr0ck3r
OpenStudy (zzr0ck3r):
no factor out a 3y from the first 2 terms and a 4 from the last 2 and tell me what you get
OpenStudy (anonymous):
ohhh ok i see! so i get 3y(2y)+4(2y)
OpenStudy (zzr0ck3r):
lets jsut look at the first two terms
6y^2+3y
factor out a 3y (devide both terms by 3y)
3y(2y+1))
OpenStudy (anonymous):
yeah i was wondering where do i get the +1 from. but now i get it completely! Thank you @zzr0ck3r!