Question

f(x)=x+e^(x)-1: By inspection f-inverse(0) and f-inverse(e)

Answer 1

0=x+e^(x)-1

Answer 2

All right, that's a little nicer:
\[
0=x+e^x-1\implies\\
0=0+e^0-1\implies\\x=0
\]And:
\[
e=x+e^x-1\implies\\
e=1+e^1-1=0+e^1\implies\\
x=1
\]Et voilá.

Answer 3

how did you figure it out?

Answer 4

There's no direct method. "By Inspection" (in solving, at least) generally means, 'try out what looks good' or 'look at something that seems like it could work.'

Answer 5

oh yea i could do that i just could do it algebraically

Answer 6

*couldn't

Answer 7

Yeah, there's no nice method, at all, for these kind of things.

Answer 8

Grazie!

Answer 9

Di niente!

Answer 10

Ciao