Question

linear algebra & differential equation

i want to know how he did this part..

Answer 1

yep

Answer 2

the part y^2-x = +c3x^-2y how did he do this?

Answer 3

to get that line from the line previous ,
multiplication my y has occurred

Answer 4

he just rewrote
\[C _{3} /2 \] as C

Answer 5

oh did he multipy everything by y?

Answer 6

Is that what you're asking?

Answer 7

im asking the part where y-xy^-1 = c3x^-2 and on the next part it becomes y^2-x = +c3x^-2y

Answer 8

and how he got it to that

Answer 9

ah

Answer 10

you're asking about completing the square...

Answer 11

\[y-xy^{-1} = c_3x^{-2}\]
multiplying both sides by y
\[yy-xy^{-1}y = c_3x^{-2}y\]

\[y^2-x = +c_3x^{-2}y\]

Answer 12

he completed the square on the LHS by adding the necessary term to both sides

Answer 13

thanks wow =)

Answer 14

sure:)

Answer 15

how did he do y^2-c3x^-2y+(c3x^-2/2)^2 = x + (c3^2x^-4/4)???

Answer 16

(c3x^-2/2)^2 = (c3^2x^-4/4)

Answer 17

he left it 'unexpanded' on the LHS so you could follow why he added that particular term (I suppose)

Answer 18

he was being nice:)

Answer 19

oh isee wow okay let me try out thanks =)

Answer 20

sure!