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OpenStudy (anonymous):

In △JKL, what is the length of line segment KL? 11.5 23radical 2 46 23radical 3

OpenStudy (anonymous):

OpenStudy (anonymous):

first using def of cos we have JL= KJcos60 = 23* 1/2= 11.5 and then KL= \[\sqrt{JL ^{2}-JK ^{2}}\] u can substitute and go..... the answer!!!!!!

OpenStudy (anonymous):

so the answer is 11.5

ganeshie8 (ganeshie8):

nope this is the same special triangle, so the answer involves \(\sqrt{3}\)

ganeshie8 (ganeshie8):

30-60-90 triangle : ◦The length of the side opposite the 60 degree angle is found by multiplying the length of the side opposite the 30 degree angle by \(\sqrt{3}\)

OpenStudy (anonymous):

23 sqrt 3

ganeshie8 (ganeshie8):

thats right! you can solve these by using soh-cah-toa as @sriramkumar hinted.. .

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