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In △JKL, what is the length of line segment KL? 11.5 23radical 2 46 23radical 3
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first using def of cos we have JL= KJcos60 = 23* 1/2= 11.5 and then KL= \[\sqrt{JL ^{2}-JK ^{2}}\] u can substitute and go..... the answer!!!!!!
so the answer is 11.5
nope this is the same special triangle, so the answer involves \(\sqrt{3}\)
30-60-90 triangle : ◦The length of the side opposite the 60 degree angle is found by multiplying the length of the side opposite the 30 degree angle by \(\sqrt{3}\)
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23 sqrt 3
thats right! you can solve these by using soh-cah-toa as @sriramkumar hinted.. .
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