Question

studying for my exam Please help!

solve:
xC3 (combination)

xPx-3 (permutation)

Answer 1

if i recall correctly there is a formula for each. try to equate them resepectively.

Answer 2

I know the formula, I'm just having a hard time solving these cause of the x

Answer 3

i know that its X!/(x-3)!3!
and 3!=6 but I'm not sure what to do with the parenthesis…because i domnt think i can distribute the !

Answer 4

i think the (x-3)! = (x-3)(x-2)(x-1)(x-0)
then you can distribute.

But I dont think you can solve this because
xC3 (combination)

xPx-3 (permutation)
Neither of them is equal to anything.

Answer 5

ohh ok! well i do know there is an answer because i have it, just having a hard time to solve it.