If (-3,0) is a point on the graph of y=f(x) which of the following must be on the graph of y=-f(x)? 1.)(-3,o) 2.)(3,0) 3.)(0,3) 4.)(3,3) 5.)(0,-3)
I know that y=f(x) is the original point, and that y=-f(x) is its mirror point...and if the f is negate that means that its a reflection across the x axis...soooo...
but theres no -3,3
wouldn't it be 1
but thats the original point
cann these work like a regular equation? like y=mx+b cuz if so you don't do anything to the y-intercept you just change the slope it will go through the same point. or no? i just haven't done these with functions
im not sure, not much of that makes sense and my book hasn't talked about it.
the lesson was just on reflections across the point of origin, x axis, and y axis.
Well if that is true. then it should be 1.
answer choice 1 that is
How can the original point of (-3,0) reflect across the x axis and still be the point (-3,0)? thats no clicking my brain
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now i've gotta go school lol. later.
Where is (-3,0)? - The 0 is a clue!
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