Did I find the derivative of the function at x=0 correctly?
y=x^2 - 3x - 1

( (x-h)^2 - 3(x-h) - 1 - x^2 + 3x +1) ) / h

(-2xh + h^2 + 3h) / h

= -2x at x=0

Question

Did I find the derivative of the function at x=0 correctly?
y=x^2 - 3x - 1

( (x-h)^2 - 3(x-h) - 1 - x^2 + 3x +1) ) / h

(-2xh + h^2 + 3h) / h

= -2x at x=0

anonymous · Answer

No its 2x-3, that in x=0 gives -3.

anonymous · Answer

Oh, its not right :(. Do you know where I messed up?

anonymous · Answer

You used -h instead of +h and lost a 3h in the middle.

anonymous · Answer

Omg, I cant believe I did that. Thanks, this question was driving me crazy because I plugged it into my calculator and got a derivative of -3.