Question

A particle is in equalibrium under the action of three forces 5 N at 53 above +ve x axis and 10N at 37 below -ve x axis find the magnitude of 3rd force?

Answer 1

i think..it is since it is not given in the question

Answer 2

5 cos37 i + 5sin 37 j = 4i + 3 j

Answer 3

10 cos 37 i + 10 sin 37 j = 8 i + 6j

Answer 4

is this correct

Answer 5

Can u correct me..

Answer 6

Find the resultant?

Answer 7

10 cos 37 (-i) + 10 sin 37 (-j) = 8 i - 6j

Answer 8

\[\sqrt{a^2 + b^2 + 2abcosx}\]

Answer 9

i got..it.....

Answer 10

\[\sqrt{125} = 5\sqrt{5}\]

Answer 11

is this correct..)