A basketball player is standing 9.5 m from the basket, which is at a height of 3.1 m. She throws the ball from an initial height of 2.0 m at an angle 35 degrees above the horizontal. The ball goes straight through the basket. Determine the initial speed of the ball.

Question

anonymous · Answer

You only need these:
$$y=y_0+v_0\sin{\alpha}*t-\frac12 g t^2$$
and
$$x=v_0\sin{\alpha}*t$$
Find t first from second eq, then plug into first eq.

anonymous · Answer

But how do I find time from the second equation when i dont have initial velocity when it's what i'm trying to find

anonymous · Answer

What i mean is to find t in term of v0 :)

anonymous · Answer

Sorry please explain further? x)

anonymous · Answer

$$t=\frac{x}{v_0\cos\alpha}$$
plug this t to first eq,

anonymous · Answer

Ok thanks a lot :)

anonymous · Answer

No problem :)