Determine the equations of any vertical asymptotes and the values of x for any holes in the graph of the following rational function. F(g)=(g-7/g^2-11g+28)

Question

anonymous · Answer

x=7 is a hole.  The other zero of the denominator is at x=4

anonymous · Answer

how did you figure that out ?

anonymous · Answer

the denom. is factorable: two roots  x=7 and x=4
x=7 makes the function = 0/0

anonymous · Answer

zero in the denom. means a vertical asymptote, unless the numerator is zero also, then it's a hole.

anonymous · Answer

can you show how you figured it ?

anonymous · Answer

factor the denominator.

anonymous · Answer

(x- _?_) (x-_?_)

anonymous · Answer

where did you get 4?

anonymous · Answer

11-7?

anonymous · Answer

Did you factor the denominator?

anonymous · Answer

i dont know how thats why i need a drawing.

anonymous · Answer

aww c'mon, you've been factoring quadratics for years now, or at least several semesters...  give it a shot..

anonymous · Answer

i dropped out. I have no hands on help.

anonymous · Answer

(x-4)(x-7)

anonymous · Answer

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anonymous · Answer

yes

anonymous · Answer

okay so you wouldnt do anything with G^2  or the g's in the equation?

anonymous · Answer

eg  x^2 + 3x -18
factors  (x+6)(x-3)      3*-6 = -18   6 -3 =3

anonymous · Answer

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