Determine the equations of any vertical asymptotes and the values of x for any holes in the graph of the following rational function. F(g)=(g-7/g^2-11g+28)
x=7 is a hole. The other zero of the denominator is at x=4
how did you figure that out ?
the denom. is factorable: two roots x=7 and x=4 x=7 makes the function = 0/0
zero in the denom. means a vertical asymptote, unless the numerator is zero also, then it's a hole.
can you show how you figured it ?
factor the denominator.
(x- _?_) (x-_?_)
where did you get 4?
11-7?
Did you factor the denominator?
i dont know how thats why i need a drawing.
aww c'mon, you've been factoring quadratics for years now, or at least several semesters... give it a shot..
i dropped out. I have no hands on help.
(x-4)(x-7)
|dw:1347832765254:dw|
yes
okay so you wouldnt do anything with G^2 or the g's in the equation?
eg x^2 + 3x -18 factors (x+6)(x-3) 3*-6 = -18 6 -3 =3
|dw:1347832969573:dw|
Join our real-time social learning platform and learn together with your friends!