Question

lim x->0 x^2-8x/x

Answer 1

When we are talking about limits, we may cancel the numerator and denominator even if the result is 0/0.\[\lim_{x \to 0} {x^2 - 8x \over x} \implies \lim_{x \to 0 {} } {\cancel x(x - 8) \over \cancel x}\]\[\implies \lim_{x \to 0}x - 8\]

Answer 2

Since \(x -8\) is a polynomial, it is continuous, which assures that you may plug in \(0 \) for \(x\).

Answer 3

thanks a straight clear answer

Answer 4

You're welcome. :-)