show that for every odd natural number n,
\[48|n^3+3n^2-n-3\]
\[| \] means divisible by
didn't you do this yesterday?
i think you solved it.
yes but we didnt get the slution
you got 8n(n+1)(n+2) you need to show that this is always divisible by 48 ...or by 3 and 16
n(n+1)(n+2) <--- this is always divisible by 3
how,i can only show 8 not even 16
if you cut that out 8, you need to show that n(n+1)(n+2) is always divisible by 2
and n(n+1) is always divisible by 2 ... this is more than sufficient.
so i am supposed to know these divisibility of 2,3
yep.
thanks can i post another one
show that n(n+1)(n+2) is always divisible by 6 ... sure you can.
three cnsecutive numbers always div by 2 and 3?
yes ... the product of three consecutive number is always divisible by both 2 and 3
THANKS CAN YOU LOOK AT THE OTHER ONE
PLS
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