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how do you find the domain of f(x)= 4/2x-3
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domain is that value of x for which the function is defined....this function is defined for all values except x=0, so domain is all real values of x except 0
It depends on whether you mean\[f(x)=\frac42x-3\qquad\text{or}\qquad f(x)=\frac4{2x-3}.\]
across the second, and why is it not zero? there can be a negative on the bottom, right?
I think @akash_809 thought you meant\[f(x)=\frac4{2x}-3.\]If you meant the second one, then the domain is all numbers except for \(x=3/2\).
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