Question

Differentiate the function:

g(u)=sqrt(2)u+sqrt(3u)

Answer 1

\[(x^{a})' = ax^{a-1}\]
sqrt(x) = x^0.5
does it helps ?

Answer 2

Oh god, I said negative exponents. I meant as a fraction. ^like above.

Answer 3

is that the same rule as d/dx(x^n)=nx^(n-1)?

and how'd you get sqrt(x)=x^0.5?

Answer 4

x^(1/2) is the definition of sqrt(x)

Answer 5

And yes differentiating it will be the same rule.

Answer 6

where'd you get x^1/2 though?

Answer 7

x^2 is "x squared"
x^(1/2) is "square root of x"

Just like x^1/3 is the cube root