calculate the derivative of f'(2) where f(x)=(square root x+2) by using the definition of the derivative
Are you sure you don't mean sqrt(x+2), instead of sqrt x + 2?
In either case, start with f'(x) = lim (delta x ->0) of [f(x+delta x) - f(x)]/delta x
yeah I mean square root(x+2)
ok, then start with my second post
Break the problem down if you still have a problem with where to start. What would be just the part which is f(x+delta x)?
If f(x) = sqrt(x+2), to get f(x+delta x), just replace x on the right side with x+delta x. What do you then have the sqrt of?