Question

solve 63(4^[4-3x])=7

Answer 1

would it be x=2/3 ?

Answer 2

no it x=2.41\3

Answer 3

how so

Answer 4

first div 63 on both sides
4^[4-3x] = 1/9
take log on both sides

Answer 5

oh okay. so how would I solve 5^[x+2] + 5^x = 24

Answer 6

when the value of x is in power of any coeff then to try to use log method

Answer 7

um okay, but can't I take the common value? which is 5^x?

Answer 8

take the common factor
5^x(5^2+1)=24
5^x(25+1)=24
5^x(26)=24