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If\[ \lim_{x \rightarrow 0}(\frac{ b-ax }{ b+ax })^{\frac{ 1 }{ x }}\] is equals 9, then express "a" in terms of "b".
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@hartnn ,@amistre64
divide by b in numerator and denom., what do u get ?
a/b in both cof.
u know the limit formula: lim x->0 (1+x)^(1/x) = ??
yap
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so whats the value of that limit ?
I got it. Thanks
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