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Mathematics 19 Online
OpenStudy (anonymous):

f(x)=1/ln(abs(x)) find the hole. I already found the V.A.:x=1,-1and H.A:y=0

OpenStudy (anonymous):

\[f(x)=1/\ln \left| x \right| \]

OpenStudy (turingtest):

what is "the hole", what are V.A and what are H.A ?

OpenStudy (anonymous):

the hole in the graph, Vertical asymptote, and Horizontal asymptote

OpenStudy (anonymous):

he means when x=0

OpenStudy (nipunmalhotra93):

yes x=0.

OpenStudy (anonymous):

but how do you find that. I already now that is the answer.

OpenStudy (anonymous):

*know

OpenStudy (anonymous):

ln|x| is defined for 0<x<0, undefined for x=0, so you'll have a hole there

OpenStudy (nipunmalhotra93):

ln|x| , 1, are all continuous except at x=0. So 1/ln(abs(x)) is also cont. at all pts except x=0.

OpenStudy (anonymous):

A hole is a removable singularity and the function does not have one.

OpenStudy (anonymous):

Thank you!!!

OpenStudy (nipunmalhotra93):

@oldrin.bataku the function does have it at x=0... right?

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