Question

Need Help In Continuity of a function .

Answer 1

post the question

Answer 2

F(x)= x+2m ,x<-3
3m(x^2)+k ,-3≤x<1
2(x^3)-m ,x>1
___________________________
(this is da multi-rule) ^^
Where F(x) is continuous at x=-3 ,at x=1
Find m,k

Answer 3

Can't u wait ?!

Answer 4

NO! BAH DOES NOT WAIT!

Answer 5

So basically plug in x=-3 into x+2m and into 3m(x^2)+k

Answer 6

-3+2m
3m(9)+k

Answer 7

Alright BAH (i wish if i was a mod >.>)
Do BAH KNOW THE ANSWER ?

Answer 8

Now equate them because you want them to meet at the same point for the function to be continuous
-3+2m=27m+k
2m-27m=k+3
-25m=k+3
k = -(25m+3)

Answer 9

i did that ,and ?

Answer 10

Do the same thing for
3m(x^2)+k
2(x^3)-m, but at x=1

Answer 11

3m+k=2-m

Answer 12

Solve the two equations

Answer 13

And everything will be revealed............................................

Answer 14

well that was my answer but i got a diff. value :/

Answer 15

:\

Answer 16

ty Bahrom :D

Answer 17

k = -(25m+3)
3m+k=2-m

3m-25m-3=2-m
-22m+m=2+3
-21m=5
m=-5/21

Answer 18

k = -(125/21 + 3) ... whatever that is