iF(X+Y)=0.17 and coxX=0.50, find sinY .
You can find x from the second equation. Now you've got x. Stick that into the first equation to get y. Then get the sin of y from 3rd.
i get x = 60
so if i put it into the cos(60+y)=0.17 hows that?
Are you sure that that is all there is to the problem? 2 things seem to be wrong with the question. 1) is cox supposed to be cos? and 2) is your trig in radians or degrees?
1) that is cos. typo error 2) it doesn't have a degree sign. it's just a number. but maybe it's a radian
Whoever worded that problem did a really poor job. You can TRY to assume it's radians but that's just an assumption and it isn't necessarily logical. I can't help you with the problem stated that way.
anyway, when you substitute 60 to cos(x+y) = 0.17 how can i solve?
Is it cos(x+y)=0.17 or (x+y)=0.17 like in your original question? Now the question changed.
i'm sorry. typo error again. it's cos(x+y)= 0.17.
how can i solve it? :)
ok 2 things.
you know cosX = 0.5, so you can get sinX. Now, use cos(a + b) = cosa x cosb - sina x sinb. You know that this equals a numerical amount since that is given and you have cosX, so you can isolate sinY and solve. This is all you have to do. Jusy work the formulas.
i got 0.3455 is it correct? :)
You got it!! Good job!
thanks a lot friend ;)
you're welcome.
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