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Mathematics 11 Online
OpenStudy (anonymous):

help please

OpenStudy (anonymous):

OpenStudy (ash2326):

Temp of 92 is recorded at 1200 feet At 2400 feet temp is 32 given that there is a linear relation between temp t and height h Do you agree with this?

OpenStudy (ash2326):

@jairo330 ??

OpenStudy (anonymous):

i dont understand. is there an equation i can use?

OpenStudy (ash2326):

We'll find an equation, it's given there is a linear relation between temp t and height h so \[t=ah+b\] here a and b are constants, we need to find them Do you get this part?

OpenStudy (anonymous):

yes

OpenStudy (ash2326):

ok, we know that Temp of 92 is recorded at 1200 feet t=92 and h=1200 so \[\large92=1200a+b \text{.............equation 1}\] and other info we have is "At 2400 feet temp is 32" so \[\large32=2400a+b\text{.............equation2}\] Canyou solve equation 1 and 2 for a and b?

OpenStudy (anonymous):

how? it's just a line

OpenStudy (ash2326):

do you know how to solve simultaneous linear equations?

OpenStudy (anonymous):

no

OpenStudy (ash2326):

We have two equations \[92=1200a+b\] \[32=2400a+b\] I'll subtract the second from the first \[92-32=(1200a+b)-(2400a+b)\] We'll get \[60=1200a+b-2400a-b\] \[60=1200a\cancel {+b}-2400a\cancel{-b}\] \[60=1200a-2400a\] \[60=-1200a\] Do you understand this? can you find "a" now?

OpenStudy (anonymous):

a=-1/20

OpenStudy (anonymous):

that makes sense

OpenStudy (ash2326):

good, now we'll find b We already have \[92=1200a+b\] put a=-1/20 in this \[92=1200\times \frac{-1}{20}+b\] \[92=-60+b\] can you find b from this?

OpenStudy (anonymous):

yes 152

OpenStudy (ash2326):

so our linear relation is \[t=\frac{-h}{20}+152\] this is the relation between temp t and height h :) dis you understand?

OpenStudy (anonymous):

yes that makes sense

OpenStudy (anonymous):

thanks a lot

OpenStudy (ash2326):

:D

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