Question

Calculate the mass of ammonia produced of 2g N2 reacts with 1g H2.

Answer 1

@TheMind @ujjwal @ajprincess

Answer 2

have you got an equation for the reaction

Answer 3

no

Answer 4

do you know the for mula for ammonia?

Answer 5

is it NH_3 ?

Answer 6

nh3

Answer 7

so far we have

\[N_2+H_2 \longrightarrow NH_3\]
right?

Answer 8

@@@UnkleRhaukus

Answer 9

can you balance the equation for number of H and N on each side?

Answer 10

UR EQ IS NT APPEARING

Answer 11

oh,

Answer 12

N_2 + H_2 ⟶ NH_3

Answer 13

so to make the product we need thee time as much H as N

Answer 14

\[N_2+3H_2\rightarrow2NH_3\]
You get no of moles required from this equation!
Convert them in terms of weight..
Find limiting reactant (the reactant whose quantity is less than required)!
limiting reactant will determine the amount of product formed!

Answer 15

Is this always the case??

Answer 16

ITS AGAIN APPEARING MATHS PROCCESING ERROR

Answer 17

i think ujjwal is right

Answer 18

N2 + 3H2 ---> 2NH3

Answer 19

So the moles are:

For nitrogen, 28g/28g/mol = 1.0 mole N2

For hydrogen 25g/2g/mole = 12.5 moles
@ujjwal right...

Answer 20

which is the limiting reagent ?

Answer 21

Obviously, hydrogen is in excess and nitrogen is the limiting reagant

Answer 22

@UnkleRhaukus

Answer 23

so according to the balanced equation the theoretical yield will be 2 moles of NH_3

Answer 24

yep! 2 mol of NH3 will be yielded!

Answer 25

the molar mass of ammonia is (1x14+3x1) g/mol

Answer 26

can you finish @Ruchi. ?

Answer 27

@mayank i'm nt getting u properly

Answer 28

@taylorrrr @ajprincess @imron07 @TheMind @Vikt0r hlp me out

Answer 29

Where are u stuck @Ruchi.?

Answer 30

Did u understand the part where the moles are calculated?