Mathematics
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OpenStudy (anonymous):
Please explain how to solve the following roots.
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OpenStudy (anonymous):
\[\sqrt{27}\]
OpenStudy (anonymous):
That is equivalent to 3*sqrt3
OpenStudy (anonymous):
So how is the answer \[\sqrt[4]{2}\]
OpenStudy (anonymous):
That is the answer i got at least.
OpenStudy (anonymous):
idk how you got that
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OpenStudy (anonymous):
\[\sqrt{27} = \sqrt{ 9 \times 3 } = \sqrt{ 9 } \times \sqrt{3} = 3\sqrt{3}\]
OpenStudy (anonymous):
Me neither.
OpenStudy (anonymous):
there is no root 2 in the prime factors of 27
OpenStudy (anonymous):
That's what I thought the answer would be. What about this one? Can you check my answer for it?
OpenStudy (anonymous):
\[\sqrt{32}\]
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OpenStudy (anonymous):
ah, now that's 16*2 = 4 root(2)
OpenStudy (anonymous):
\[\sqrt{32}=\sqrt{16x2}=\sqrt{8x2x2}=\sqrt{4x2x2x2}=\sqrt{2x2x2x2}= 2\sqrt{4}\]
OpenStudy (anonymous):
tssss
OpenStudy (anonymous):
\[\sqrt{32} = \sqrt{ 16 \times 2 } = \sqrt{16} \times \sqrt{2} = 4 \sqrt{2}\]
OpenStudy (anonymous):
Oh. Well then how about this one. \[\sqrt{40}=\sqrt{4x10}=\sqrt{2x2x5x2}=5\sqrt{4}\]
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OpenStudy (anonymous):
it's ok up to 4x10
OpenStudy (anonymous):
agfter that\[\sqrt{4} \times \sqrt{10} = 2 \sqrt{10}\]
OpenStudy (anonymous):
You are looking to break down a number into the product of a "good square" ( like 4,9,16,25,36 etc) and anohter number
OpenStudy (anonymous):
I am totally not understanding this.
OpenStudy (anonymous):
ok, hold on
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OpenStudy (anonymous):
lets look at \[\sqrt{40}\]
OpenStudy (anonymous):
We want to break that 40 into 2 pieces
OpenStudy (anonymous):
one piece has to be a square the other doesnt matter
OpenStudy (anonymous):
You know what a square is?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
ok, a square is a number multiplied by itsself.
OpenStudy (anonymous):
\[1^2 = 1 \times 1 = 1\]
OpenStudy (anonymous):
\[2^2 = 2 \times 2 = 4\]
OpenStudy (anonymous):
got it
OpenStudy (anonymous):
so the squares (up to 10 are) 1,4,9,16,25,36,49,64,81,100
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OpenStudy (anonymous):
what you want to do with the number under the root sign is break it up into 2 parts, 1 square, the other not
OpenStudy (anonymous):
\[\sqrt{40}\]
OpenStudy (anonymous):
we have 40, that breaks down into 4 * 10
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
with 4 being the sqaure and 10 being not a square
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
you're always looking for the largest square to fit
OpenStudy (anonymous):
like with
\[\sqrt{32}\]
OpenStudy (anonymous):
32 breaks down into 4x8 but also 16x2
OpenStudy (anonymous):
you want to choose 16x2
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OpenStudy (anonymous):
after that, you can break up the root sign, and simply take the root of the square
OpenStudy (anonymous):
and voila, you're done
OpenStudy (anonymous):
\[\sqrt{40} = \sqrt{4 \times 10 } = \sqrt{4} \times \sqrt{10} = 2 \times \sqrt{10} = 2 \sqrt{10}\]
OpenStudy (anonymous):
the \[\sqrt{4} = 2\]
OpenStudy (anonymous):
ok so 40 would be 4*10=2*2*5*2= \[5\sqrt{2}\]
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OpenStudy (anonymous):
nope, 40 = 4*10, you dont break in into any more pieces
OpenStudy (anonymous):
40 = 2 * 2 * 2 * 5 of course, but that doesnt really help
OpenStudy (anonymous):
So I am making this more complicated then this has to be?
OpenStudy (anonymous):
you need to break it into 2 pieces, 1 piece a nice square, the other just a number
OpenStudy (anonymous):
you're doing too much, yeah, and in the process you're confusing yourself
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OpenStudy (anonymous):
Oh my gosh. I feel so stupid.
OpenStudy (anonymous):
another example, try \[\sqrt{50}\]
OpenStudy (anonymous):
nah, dont feel stupid for trying. People who don't try are stupid
OpenStudy (anonymous):
:) The answer is 10x5= \[10\sqrt{5}\]
OpenStudy (anonymous):
almost right
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OpenStudy (anonymous):
it's 25*2 , can you give me the answer now?
OpenStudy (anonymous):
\[25\sqrt{2}\]
OpenStudy (anonymous):
\[\sqrt{50} = \sqrt{25*2} = \sqrt{25} \times \sqrt{2} = 5\sqrt{2}\]
OpenStudy (anonymous):
almost right again, you need to root the 25
OpenStudy (anonymous):
\[5\sqrt{2}\]
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OpenStudy (anonymous):
yup
that's the only trick you'll need for this kind of questions
OpenStudy (anonymous):
\[\sqrt{32}=16x2=16\sqrt{2}=8\sqrt{2}\]
OpenStudy (anonymous):
almost right
OpenStudy (anonymous):
\[\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4 \sqrt{2}\]
OpenStudy (anonymous):
cause \[\sqrt{16} = 4\]
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OpenStudy (anonymous):
not 8
OpenStudy (anonymous):
i gotto go eat now, kids are screaming they're hungry ;)
OpenStudy (anonymous):
I thought that was the answer. Thank you SO much for your help! I am going to try this on my own now. Bye! :D