Question

sin(2A)/[1-(sinA)^2]=2tan(A)
can anyone start me out??

Answer 1

ok.. you need to know a couple of things to start this problem

1. sin(2A) = 2sin(A)cos(A)

2. 1 - sin^2(A) = cos^2(A) .... or cos(A)cos(A)

3. \[\tan(A) = \frac{\sin(A)}{\cos(A)}\]

then you fraction becomes

\[\frac{2\sin(A)\cos(A)}{\cos(A)\cos(A)}\]

eliminate the common factor

and you should have your answer

Answer 2

oh my goodness! thank you so much!