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Mathematics 20 Online
OpenStudy (anonymous):

Statistics: \[\mu=28\] \[\sigma=5\] If \[P(z\le z_0)=0.12\] How do I use the attached table to come to the conclusion that \[z_0=-1.175\]?

OpenStudy (anonymous):

OpenStudy (zarkon):

look up .12 in the middle of the table

OpenStudy (zarkon):

or the numbers closest to .12

OpenStudy (anonymous):

You mean here?

OpenStudy (zarkon):

no...the middle of the table...middle of the paper

OpenStudy (anonymous):

No I think you mean here

OpenStudy (anonymous):

right?

OpenStudy (zarkon):

no

OpenStudy (anonymous):

Where?

OpenStudy (zarkon):

middle! ... don't look along the edge yet

OpenStudy (anonymous):

here?

OpenStudy (zarkon):

yes...but there is another number that is really close to .12

OpenStudy (anonymous):

.1190

OpenStudy (zarkon):

yes...what are the z values for those 2 numbers

OpenStudy (anonymous):

but how did they come to the conclusion that z_0=-1.175?

OpenStudy (zarkon):

answer my last question first

OpenStudy (anonymous):

-1.1 and .07 and .08....ah I see Therefore -1.75 since it between .1190 and .1210

OpenStudy (zarkon):

-1.17 and -1.18 take average of the two gives -1.175

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