Question

y = sec θ tan θ differentiate help?

Answer 1

that's just sec(theta), since the derivative of sec(x) is sec(x)tan(x)

Answer 2

use multiply rule :
y=uv
y'=u'v+uv'

Answer 3

whoope, I gave you the integration of secxtanx. Sorry, ignore me...

Answer 4

ok, nope :)
do u know what the first derivative of sec(x) ?

Answer 5

the derivative of sec(x) is sec(x)tan(x)
the derivative of tan(x) is:
\[\sec ^{2}x\]

Answer 6

yea, that's right derivative of sec(x) is sec(x)tan(x)
and u know that integral is anti derivative, so
int(sec(x)tan(x)) dx can be sec(x)

Answer 7

I thought you were finding the derivative of sec(x)tan(x)?

Answer 8

like what i said before, use multiply rule : y=uv => y'=u'v+uv'
and u must know that : derivative of sec(x) is sec(x)tan(x) and
derivative tan(x) is (sec(x))^2

Answer 9

The complete answer should be:
\[\sec ^{3}x + \tan ^{2}xsecx\]
OR
\[secx (\sec ^{2}x+\tan ^{2}x)\]
If you are finding the derivative.