Question

Question! Screenshot attached. Need someone to explain how to get the right answer.

Answer 1

that red graph is the graph of the equation you have listed in the box \(\large y=\sqrt[3]{x-1}+3 \)

Answer 2

I suppose you got this wrong by testing some values and seeing that the x,y worked out for the given equation?

Answer 3

Just to be clear, you were given that graph with that equation and asked to say true or false, is that right?

Answer 4

Well, it's true. That graph and that equation go together.

Answer 5

Did you put false?

Answer 6

OK, we want to test a few values of x and y so we could choose 0,2,8 for x on the plus side and say -8 on the negative side and then calculate what the equation gives for y.

In each case we have a match.

Maybe you got confused

Answer 7

Actually plus/minus 9 is better than 8

Answer 8

No need, just test enough x and y values...

Answer 9

You might want to do odd/even and other things if you were trying to sketch a graph but in this case it is all given.

Answer 10

OK feed in -9 and we get cuberoot-8 +3 = 1

Answer 11

i will but after he shows you his method.... i don't like to "cut" in....

Answer 12

I'm done, do the same with the other values....:-)

Answer 13

I did

Answer 14

K, cuberoot(9-1) +3 = 5

Answer 15

Another point?

Answer 16

Why don't you pick an x value....

Answer 17

That one is OK, it's on the graph so we can see it.

So plug x=4 into the given equation.

Answer 18

What do you get for y?

Answer 19

OK:-) It comes out to 4.44 so you can see on the graph that x =4 , y= 4.44 is on the curve

(it's not so easy to see as the other numbers which I picked)

Answer 20

Ciao! (Try it with x=2)

Answer 21

sorry... got caught up with another problem....
the parent function \(\large f(x) =\sqrt[3]{x} \) can be transformed to the red graph you have by translating f one unit to the right and 3 units up.....
\(\Large f(x-1)+3 \)

Answer 22

She posted it again new....