The problem above shows some values for the
function f. If f(x)=ka to the x power for some
constants k and a, what is the value of a?
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OpenStudy (anonymous):
x= -1,0,1.
f(x)=1/8,1/2,2
OpenStudy (anonymous):
tips?
OpenStudy (chihiroasleaf):
f(x) = ka to the x power,
so \[f(x) = \left( ka \right)^{x}\]
or \[f(x)=ka ^{x}\]
you just need to substitute the value of x into the function, then you'll have three equations, solve the equation to find k and a
OpenStudy (anonymous):
k
OpenStudy (anonymous):
ahh
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OpenStudy (anonymous):
1/4 equal a when k=1/32?
OpenStudy (anonymous):
opps
OpenStudy (anonymous):
a=4 when k=1/8?
OpenStudy (anonymous):
that's the correct answer in the book
OpenStudy (anonymous):
but why?
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OpenStudy (chihiroasleaf):
are you sure that it's the result?
the given informations are f(-1) = 1/8 ; f(0)=1/2 ; f(1) = 2, right?
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
don't you just plug in values for f(x)=ka to the x power?
OpenStudy (anonymous):
1/8=k4 to the negative one power
OpenStudy (anonymous):
1/8=1/4k
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OpenStudy (anonymous):
k=1/2
OpenStudy (anonymous):
1/8=1/2 times 1/4
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
are did I do it incorrectly?
OpenStudy (chihiroasleaf):
where do you get 1/8 = k4 and 1/8 = 1/4k ?
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OpenStudy (anonymous):
let me try out a simpler equatio
OpenStudy (anonymous):
2=k4 to the first power
OpenStudy (anonymous):
2=4k
OpenStudy (anonymous):
1/2=k
OpenStudy (anonymous):
2=1/2 times 4=2
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OpenStudy (chihiroasleaf):
\[f(x)= ka ^{x}\]
\[f(-1)=\frac{ 1 }{ 8 }\]
\[ka^{-1}=\frac{1}{8}\]
\[frac{k}{8}=\frac{1}{8}\]
OpenStudy (anonymous):
wah?
OpenStudy (anonymous):
I thought i Just had to plug in values for the equation f(x)=ka to the x power?
OpenStudy (anonymous):
doesn't f(x) equal y?
OpenStudy (chihiroasleaf):
*the last row
\[\frac{ k }{ a }=\frac{ 1 }{8 }\]
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OpenStudy (anonymous):
why doesn't 2= k(4 to the first power) work?
OpenStudy (chihiroasleaf):
yes, f(x) equal to y
you want to find a right?
OpenStudy (anonymous):
yeah....
OpenStudy (anonymous):
2=4k
OpenStudy (anonymous):
1/2=k, right?
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OpenStudy (chihiroasleaf):
yes, k = 1/2
but I get it by using the second information
f(0) = 1/2, so
k x a^0 = 1/2
k = 1/2
OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
do
OpenStudy (anonymous):
so
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OpenStudy (anonymous):
1/2=ax to the 0 power
OpenStudy (anonymous):
1/2=a
OpenStudy (anonymous):
k to the 0 power
OpenStudy (anonymous):
the answer is D
OpenStudy (anonymous):
4
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OpenStudy (anonymous):
not 1/2...
OpenStudy (anonymous):
wait a sec...
OpenStudy (anonymous):
1/2=ka to the 0 power
OpenStudy (anonymous):
1/2=k
OpenStudy (anonymous):
1/2=1/2a to the x power...
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OpenStudy (chihiroasleaf):
yes, then plug in the value of k into the first equation you have, k/a = 1/8 , then you'll get a
OpenStudy (anonymous):
you can do that?
OpenStudy (anonymous):
could you do 1/2=1/2(4 to the 0 power)
OpenStudy (anonymous):
could you do that?
OpenStudy (anonymous):
I got k=1/2
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OpenStudy (anonymous):
tips?
OpenStudy (chihiroasleaf):
if you use that equation, any value of a will satisfy the equation since a^0 = 1, so, you cannot use that equation to find a..,
yes, k = 1/2, then to find a , plug in k = 1/2 into k/a = 1/8
OpenStudy (anonymous):
where did you get a, though?
OpenStudy (anonymous):
where did you get the 1/8?
OpenStudy (chihiroasleaf):
you have f(-1) = 1/8
so, k x a^(-1) = 1/8
k/a = 1/8
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