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Mathematics 21 Online
OpenStudy (anonymous):

Umm..question? Need someone to show me step by step.

OpenStudy (anonymous):

What is the question?

OpenStudy (anonymous):

Is the question within parenthesis and the ^2 on the out side?

OpenStudy (anonymous):

ok so look at the top section first 12x^2y^2. Start with the order of operations.

OpenStudy (anonymous):

Parenthesis exponents multiplication and division addition and subtraction.

OpenStudy (anonymous):

Are there Exponents with in the question?

OpenStudy (anonymous):

so start with those from left to right.

OpenStudy (anonymous):

I would believe so

OpenStudy (anonymous):

fromm that equation of x^2 + y^2 it would be... x^2Y^2 you do not add them together because they are two diff varibales

OpenStudy (anonymous):

you said the steps and you say you know how to do it...?

OpenStudy (anonymous):

\[\frac{12x^2y^2}{3xy^4}=\frac{4x}{y^2}\] is as start

OpenStudy (anonymous):

since \(\frac{12}{3}=4\) and \(\frac{x^2}{x}=x\) and \(\frac{y^2}{y^4}=\frac{1}{y^2}\) by cancelling

OpenStudy (anonymous):

then i guess you have to square the the whole thing and figure out \[\left(\frac{4x}{y^2}\right)^2\] but that should be ok

OpenStudy (anonymous):

\(4^2=16,x^2=x^2,( y^2)^2=y^4\) so your final answer is \[\frac{16x^2}{y^4}\]

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