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Mathematics
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OpenStudy (anonymous):
Umm..question? Need someone to show me step by step.
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OpenStudy (anonymous):
What is the question?
OpenStudy (anonymous):
Is the question within parenthesis and the ^2 on the out side?
OpenStudy (anonymous):
ok so look at the top section first 12x^2y^2. Start with the order of operations.
OpenStudy (anonymous):
Parenthesis
exponents
multiplication and division
addition and subtraction.
OpenStudy (anonymous):
Are there Exponents with in the question?
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OpenStudy (anonymous):
so start with those from left to right.
OpenStudy (anonymous):
I would believe so
OpenStudy (anonymous):
fromm that equation of x^2 + y^2 it would be... x^2Y^2 you do not add them together because they are two diff varibales
OpenStudy (anonymous):
you said the steps and you say you know how to do it...?
OpenStudy (anonymous):
\[\frac{12x^2y^2}{3xy^4}=\frac{4x}{y^2}\] is as start
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OpenStudy (anonymous):
since \(\frac{12}{3}=4\) and \(\frac{x^2}{x}=x\) and \(\frac{y^2}{y^4}=\frac{1}{y^2}\) by cancelling
OpenStudy (anonymous):
then i guess you have to square the the whole thing and figure out
\[\left(\frac{4x}{y^2}\right)^2\] but that should be ok
OpenStudy (anonymous):
\(4^2=16,x^2=x^2,( y^2)^2=y^4\) so your final answer is
\[\frac{16x^2}{y^4}\]
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