Question

If you have 25cm3 of 0.50mol.dm-3 HCL and 25cm3 of 0.50mol.dm-3 NaOH and at some point you add them together. The question is: calculate the number of moles of NaOH used. So I would use c=n/V -> n=cV, but, is V the total Volume or just the volume of NaOH?

Answer 1

\[25cm^{3} \] \[0.5mol.dm^{-3}\]

Answer 2

@myininaya

Answer 3

@ash2326