Question

Find dy / dx by implicit differentiation:


5 + 3 x = sin (x y^7)

Answer 1

\(\large 5 + 3 x = sin (x y^7) \)
\(\large [5 + 3 x]' = [sin (x y^7)]' \)
\(\large [5]' + [3 x]' = cos (x y^7) \cdot [xy^7]' \)
\(\large 0+3 = cos (x y^7) \cdot [xy^7]' \)

Answer 2

@monroe17 Now your next step is applying product rule:
( xy^7) ' = ...

Answer 3

sorry.... afk for a bit...
yes, can you do the product rule on [xy^7]' ???