What is the axis of symmetry of the parabola given by the equation x = -1/32 y2?

Question

anonymous · Answer

is your equation $$x=\frac{-y^2}{32}$$ if it is then your axis of symmetry is where the vertex is at, and where the parabolat starts to mirrow itself.
In this case, it is the x-axis.

anonymous · Answer

$$x=\frac{ 1 }{32 }y^2$$

anonymous · Answer

but its negative sorry

anonymous · Answer

is it 1 divided by 32?  Regardless, that term before the y^2 is a constant. the answer is still the same.

anonymous · Answer

$$x=-\frac{ 1 }{ 32 }y^2$$

anonymous · Answer

The only thing that would shift the axis of symmetry would be a $$x=ay^2 +by+c$$ where the b  value isn't zero. Otherwise, your axis of symmetry would be on the axis of the dependent variable.

anonymous · Answer

The a value, your $$\frac{-1}{32}$$ decides how "wide" your parabola is and which direction it faces (left for negative, right for positive)
The c value shifts the vertex of the parabola left or right depending on the value. If it's zero, the vertex is at point (0,0)