Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

2. Fill in the Blank: When producing ball bearings, the probability that one is too small is .20, the probability that a bearing is marred is .17, and the probability that a bearing has both defects is .02. Find the probability that a ball bearing has neither defect. 3. Fill in the Blank: You roll two dice, one red and one green. Find the probability that at least one of the die is a 2 given that the total of the dice is 8.

OpenStudy (anonymous):

whoa nelly which one do you want to do first?

OpenStudy (anonymous):

whichever..doesn't matter! :)

OpenStudy (anonymous):

probability it has one defect or another or both is \[.20+.17-.02\] as it is the same as \[P(A\cup B)=p(A)+P(B)-P(A\cap B)\]

OpenStudy (anonymous):

compute that number, then subtract it from 1 to get your answer

OpenStudy (anonymous):

so I got .65 for the answer.

OpenStudy (anonymous):

second one we do by counting there are the ways to get an "8" \[\{(2,6),(3,5),(4,4),(5,3),(6,2)\}\] so your sample space contains those 5 pairs count the number that have one die as a 2, your answer will be clear

OpenStudy (anonymous):

i think your arithmetic is wrong on the first one

OpenStudy (anonymous):

.81 for the first one?

OpenStudy (anonymous):

oh no sorry, my arithmetic is wrong!!

OpenStudy (anonymous):

it was \(.65\) you were right the first time, sorry

OpenStudy (anonymous):

ok great

OpenStudy (anonymous):

second one clear?

OpenStudy (anonymous):

i'm confused on the second one

OpenStudy (anonymous):

you are given that the total is 8 right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so i wrote what the possibilities are it is this: \[\{(2,6),(3,5),(4,4),(5,3),(6,2)\}\]

OpenStudy (anonymous):

those are the only 5 possible ways to get an 8 if you roll two dice hope it is clear what those ordered pairs represent, the green die, and the blue die

OpenStudy (anonymous):

then you count, out of those 5 possibilities, how many contain a 2 ?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

right. so your answer?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

oh no! you are looking for a probability,

OpenStudy (anonymous):

you forgot your denominator

OpenStudy (anonymous):

2/5?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

which would be .4?

OpenStudy (anonymous):

yes it would, if you like decimals

OpenStudy (anonymous):

i hope you look over the work we just did and convince yourself that it is really easy, especially the second one. just a matter of counting really

OpenStudy (anonymous):

thank you for your help.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!