2. Fill in the Blank: When producing ball bearings, the probability that one is too small is .20, the probability that a bearing is marred is .17, and the probability that a bearing has both defects is .02. Find the probability that a ball bearing has neither defect. 3. Fill in the Blank: You roll two dice, one red and one green. Find the probability that at least one of the die is a 2 given that the total of the dice is 8.
whoa nelly which one do you want to do first?
whichever..doesn't matter! :)
probability it has one defect or another or both is \[.20+.17-.02\] as it is the same as \[P(A\cup B)=p(A)+P(B)-P(A\cap B)\]
compute that number, then subtract it from 1 to get your answer
so I got .65 for the answer.
second one we do by counting there are the ways to get an "8" \[\{(2,6),(3,5),(4,4),(5,3),(6,2)\}\] so your sample space contains those 5 pairs count the number that have one die as a 2, your answer will be clear
i think your arithmetic is wrong on the first one
.81 for the first one?
oh no sorry, my arithmetic is wrong!!
it was \(.65\) you were right the first time, sorry
ok great
second one clear?
i'm confused on the second one
you are given that the total is 8 right?
yes
so i wrote what the possibilities are it is this: \[\{(2,6),(3,5),(4,4),(5,3),(6,2)\}\]
those are the only 5 possible ways to get an 8 if you roll two dice hope it is clear what those ordered pairs represent, the green die, and the blue die
then you count, out of those 5 possibilities, how many contain a 2 ?
2
right. so your answer?
2
oh no! you are looking for a probability,
you forgot your denominator
2/5?
yes
which would be .4?
yes it would, if you like decimals
i hope you look over the work we just did and convince yourself that it is really easy, especially the second one. just a matter of counting really
thank you for your help.
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