Question

Does there exist as set that consists of every number

Answer 1

a set?

Answer 2

\[(-\infty,\infty)\]

Answer 3

thats is only real numbers

Answer 4

are complex number actually numbers? lol

Answer 5

sure they are

Answer 6

technically it's a mathmatical fix of something that didn't work out .

but the set would be a space

Answer 7

{x|x=x}

Answer 8

You could try {±1, ±2, ±3, ±4, ±5, ... ±10,000 ... ±x ... ±x^2±, ±x^3±, ... ±x^10,000±}

Answer 9

the set of numbers....

Answer 10

I really depends on what you are calling numbers. For most people, the set of complex numbers is "all" the numbers. This is because of the Fundamental Theorem of Algebra, which states that a polynomial with complex coefficients of degree n must have n roots. In a sense, what this is saying is there is no larger set sitting above the complex numbers.

This is not like the real numbers, where if you have a polynomial with real coefficients of degree n, you can find at most n roots, but there may be less than n. Look at the equation:\[x^2+1=0\] It has no real roots, which leads you to think there may be a "larger set" of numbers above it (the complex numbers).

Answer 11

Now there are other sets which behave like the complex numbers, but are not typically what people call numbers. These sets are called Fields.

http://en.wikipedia.org/wiki/Field_(mathematics)

Answer 12

{x/x=x} by Bertrand Russell "a set of all sets"

Answer 13

@AbhimanyuPudi I'm no mathematician, so maybe this is stupid, but wouldn't that exclude 0?

Answer 14

\[U=\{x|x=x\}\]

Answer 15

What that? Set of all sets?

Answer 16

is it/

Answer 17

You can understand U as being all elements of the applicable domain.

If the domain is ZFC, then U would be a "class" of all sets.

Answer 18

/ means "such that" @UnkleRhaukus

Answer 19

@geoffb That is not (x divided by x = x)...That is (x such that x=x)

Answer 20

Oh... |.

Gotcha. Thank you.