Question

Please help me with the steps to solve the following:
Factor completely (f+4)(2f-3)+(f+4)(f+4)

Answer 1

Each term has a f+4 in common, so factor that out to get


(f+4)(2f-3)+(f+4)(f+4)


(f+4)[(2f-3)+(f+4)]


(f+4)(2f-3+f+4)


(f+4)(3f+1)

Answer 2

Oh ok so is (f+4)(3f+1) the final result or do i need to go further such as 3f+12f+f4=15f+4 to complete?

Answer 3

(f+4)(3f+1)

is as factored as it gets

Answer 4

what you have isn't correct (it looks like you're expanding it out again, but that's the opposite of factoring)

Answer 5

Oh I get it now...I thought I had to keep going. So to do another problem to factor completely such as 121p(square)-121p would be 121(p-1)p?

Answer 6

that's one way to do it, you can also write it as

121p(p-1)

Answer 7

Great! Thank you so much for your help.

Answer 8

yw