Please help me with the steps to solve the following:
Factor completely (f+4)(2f-3)+(f+4)(f+4)

Question

Please help me with the steps to solve the following: 
Factor completely (f+4)(2f-3)+(f+4)(f+4)

jim_thompson5910 · Answer

Each term has a f+4 in common, so factor that out to get


(f+4)(2f-3)+(f+4)(f+4)


(f+4)[(2f-3)+(f+4)]


(f+4)(2f-3+f+4)


(f+4)(3f+1)

anonymous · Answer

Oh ok so is (f+4)(3f+1) the final result or do i need to go further such as 3f+12f+f4=15f+4 to complete?

jim_thompson5910 · Answer

(f+4)(3f+1)

is as factored as it gets

jim_thompson5910 · Answer

what you have isn't correct (it looks like you're expanding it out again, but that's the opposite of factoring)

anonymous · Answer

Oh I get it now...I thought I had to keep going. So to  do another problem to factor completely such as 121p(square)-121p would be 121(p-1)p?

jim_thompson5910 · Answer

that's one way to do it, you can also write it as

121p(p-1)

anonymous · Answer

Great!  Thank you so much for your help.

jim_thompson5910 · Answer

yw