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A Geometric Progression in which all terms are positive has common ratio r. The sum of first n terms is less than 90% of the sum to infinity. Show that r^n>0.1.
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know the formulas for sum of GP, finite and infinite ?
Yep.
I tried solving with the formulas but could not get the answer.
Sum of 'n' terms < 0.9 sum to infinity
a(1-r^n) / (1-r) <0.9 a/ (1-r)
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now cancel a and 1-r from both sides
I did it this way. \[a(1-r ^{n})\div( r-1) < 0.9a \div (1-r)\]
the denominator in sum of n terms is 1-r not r-1
and u can cancel a and 1-r from both sides to get 1-r^n <0.9 did u get this ?
Oh okay. That was the mistake I was making. Thank you so much for helping! :)
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welcome ^_^
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