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Show all work simplify (2x^2+8x-42)/(x^2+12x+35)
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\[2x^2+8x-42/x^2+12x+35\]
First un factor both the demonimater and numerator
\[2x^2+8x-42 ---> 2(x^2+4x+21) ---> 2(x+7)(x-3)\]
the u do the same for the denominator
and that would be\[x^2+12+35 ---> (x+5)(x+7)\]
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so now your equation should look like
\[2(x+7)(x-3)/(x+7)(x+5)\]
so X+7 cancels X+7 in both denominator and numerator
so that leaves you with
\[2(x-3)/(x+7)\]
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then distribute the 2 and u should get as a final anwser of
\[2x+6/x+5\]
Awesome. Thank you sooooo much.
XD no problem :D
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