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Mathematics 18 Online
OpenStudy (anonymous):

Show all work simplify (2x^2+8x-42)/(x^2+12x+35)

OpenStudy (anonymous):

\[2x^2+8x-42/x^2+12x+35\]

OpenStudy (anonymous):

First un factor both the demonimater and numerator

OpenStudy (anonymous):

\[2x^2+8x-42 ---> 2(x^2+4x+21) ---> 2(x+7)(x-3)\]

OpenStudy (anonymous):

the u do the same for the denominator

OpenStudy (anonymous):

and that would be\[x^2+12+35 ---> (x+5)(x+7)\]

OpenStudy (anonymous):

so now your equation should look like

OpenStudy (anonymous):

\[2(x+7)(x-3)/(x+7)(x+5)\]

OpenStudy (anonymous):

so X+7 cancels X+7 in both denominator and numerator

OpenStudy (anonymous):

so that leaves you with

OpenStudy (anonymous):

\[2(x-3)/(x+7)\]

OpenStudy (anonymous):

then distribute the 2 and u should get as a final anwser of

OpenStudy (anonymous):

\[2x+6/x+5\]

OpenStudy (anonymous):

Awesome. Thank you sooooo much.

OpenStudy (anonymous):

XD no problem :D

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