Question

3(b^5c)^-2 Cannot remember how to simplify this..Do i distribute? Help:)

Answer 1

\[3(b ^{5c})^{-2}\]
______________________________
first do \[(b ^{5c})^{-2}\]
-2 * 5c = -10c so \[(b ^{-10c})\]
______________________________
which is 1/\[(b ^{10c})\] because a negative exponent is the same as the 1 over the monomial

Now multiply 1/ \[(b ^{10c})\] by 3, so the answer is \[3/(b ^{10c})\]

Answer 2

Awesome thank you...Actually the "c" is not an exponent though..Does the same action apply?

Answer 3

If it is just -C you don't put it under 1 if that's what you're asking? but if its X^-c then you put it under one without the negative.