solve for x-3y=5 and -4x+6y=-15
What do you think the first step is to do? You can substitute/eliminate.
I can solve for one of the equations for x-3y=15
So you want to do substitution? Where you have what one variable equals and you plug it into the other equation? Such as x=some_numbers In this case x-3y=15 You add the 3y to the other side so you have x=16+3y Do you know what the next step is?
I would plug it in to the other equarion would it be -4{16+3y)+6y=-15
Correct! Now what does that distribute out to equal?
Y= -49/6?
Oh, I'm sorry I made a typo! In this case x-3y=15 You add the 3y to the other side so you have* x=16+3y* <- that should equal x=5+3y
so you get -4(5+3y)+6y=-15
I tried figuring it out would the answer be (38/5,-5/6)?
-5/6 is correct but the other one isn't, where do you plug y=-5/6 back into, to solve for x?
Would it be 5/2 i would plug in -5/6 to x-3y=5
Yup, I'm pretty sure that is correct!
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