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Mathematics 16 Online
OpenStudy (anonymous):

Calculus problem?

OpenStudy (anonymous):

\[3x +x \tan x\] Find dy/dx

OpenStudy (anonymous):

did you attempt?

OpenStudy (anonymous):

hint , you will need to use product rule

OpenStudy (anonymous):

yep, it's product rule 3x + (1) (tanx) + sec^2x(x)

OpenStudy (anonymous):

that's my first step

OpenStudy (anonymous):

a minor error instead of having 3x + (1) (tanx) + sec^2x(x) you should have 3+tanx+ (x)*(sec^2x)

OpenStudy (anonymous):

how is that? can you show me step by step?

OpenStudy (anonymous):

sure,

OpenStudy (anonymous):

|dw:1349741102462:dw|

OpenStudy (anonymous):

hmm i never done it with d/dx before...

OpenStudy (anonymous):

so the format seems unfamiliar... sorry

OpenStudy (anonymous):

no worries you can use the prime ' NOTATION instead of writing d/dx

OpenStudy (anonymous):

in simple terms, we find derivative of 3x which is 3 derivative of xtanx which is 1*tanx + x * sec^2x

OpenStudy (anonymous):

Oooohh i forgot to take the derivative of 3! ok i get it now

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