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Calculus problem?
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\[3x +x \tan x\] Find dy/dx
did you attempt?
hint , you will need to use product rule
yep, it's product rule 3x + (1) (tanx) + sec^2x(x)
that's my first step
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a minor error instead of having 3x + (1) (tanx) + sec^2x(x) you should have 3+tanx+ (x)*(sec^2x)
how is that? can you show me step by step?
sure,
|dw:1349741102462:dw|
hmm i never done it with d/dx before...
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so the format seems unfamiliar... sorry
no worries you can use the prime ' NOTATION instead of writing d/dx
in simple terms, we find derivative of 3x which is 3 derivative of xtanx which is 1*tanx + x * sec^2x
Oooohh i forgot to take the derivative of 3! ok i get it now
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