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OpenStudy (anonymous):
through (3,-4); perpendicular to x+5y=-5
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OpenStudy (anonymous):
what?
OpenStudy (aripotta):
i think we have to write the equation of the line that goes through point (3,-4) and is perpendicular to x + 5y = -5
OpenStudy (anonymous):
yeah, i need help solving it
OpenStudy (aripotta):
what form does it need to be in?
OpenStudy (aripotta):
standard?
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OpenStudy (anonymous):
function notation
OpenStudy (aripotta):
idk what that is :l is that like slope-intercept?
OpenStudy (anonymous):
its like f(x)= mx+b
OpenStudy (aripotta):
hmm ok. well first i would make x+5y=-5 into slope-intercept so we can see what the slope is
OpenStudy (aripotta):
do you know how to do that?
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OpenStudy (anonymous):
yes
OpenStudy (aripotta):
so what did you get when you put it into slope-intercept form?
OpenStudy (anonymous):
y=1/5x-1
OpenStudy (aripotta):
yes, but 1/5x needs to be negative.
so what's going to be the slope of our perpendicular line?
OpenStudy (aripotta):
perpendicular lines have negative reciprocal slopes of each other
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OpenStudy (aripotta):
so if the slope of our first line is -1/5 what's the slope of our perpendicular line?
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