Question

A car accelerates from rest at -3.00 m/s^s

Answer 1

what are you finding?

Answer 2

I'm trying to find the velocity after 5.0 seconds and the displacement after the same time

Answer 3

which physics are you taking?

Answer 4

Honors Physics

Answer 5

do you use calculus in it?

Answer 6

if not,
v = vi + at

Answer 7

vi is initial velocity, which is zero because it starts from rest

Answer 8

Okay

Answer 9

x = xi + vi t + 1/2 at^2

Answer 10

where xi is initial position and is zero

Answer 11

vi is also zero

Answer 12

So 0+0+1/2 at^2?

Answer 13

yes

Answer 14

i just gave you those equations because they are standard physics equations

Answer 15

and are applicable to almost every kinematics situation

Answer 16

sometimes the objects don't start at rest or start in another place
another good one to know is vf^2 = vi^2 + 2a(xf - xi)
vf is final velocity, vi is initial velocity, xf is final position, and xi is initial position

Answer 17

at would be the 5 seconds?

Answer 18

t = 5
so (.5) * (-3) * (5^2)
is that what you meant?

Answer 19

Yes