Question

log2(x) + log2(x+3) = log2(2)

Answer 1

\[\log_{2} (x*(x+3)) = \log_{2} (2)\rightarrow \log_{2} (x ^{2}+3x) = 1\]

Answer 2

how do i find "x"?

Answer 3

a good rule to know is \[n^{\log_{n} (x)} = x\] where n can be any number (in your case it is 2)

Answer 4

\[2^{1}=x ^{2}+3x\]

Answer 5

You know that log(x) + log(y) = log(xy) so, your equation is equivalent to
log2(x(x+3)) = log2(2)
which means that x(x+3) = 2 iff x^2+3x-2=0 which can be calculated using delta

Answer 6

\[ x ^{2}+3x -2 = 0\]

Answer 7

this you should now know what to do.

Answer 8

thank you

Answer 9

you're welcome