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Mathematics 16 Online
OpenStudy (anonymous):

Prove: tan y/(tan^2 y - 1) = 1/ (tan y - cot y)

hartnn (hartnn):

write the tan y of numerator as 1/ cot y

OpenStudy (anonymous):

So you mean I should get (1/cot y)/(tan^2y - 1)?

hartnn (hartnn):

yes, so its 1/(cot y (tan^2 y -1) ) you know what cot y * tan y is, right ?

OpenStudy (anonymous):

I got it now! cot y * tan y = 1, so when I distribute cot y... 1/cot y(tan^2y -1) 1/ tan y(1) - cot y I can't believe I didn't catch it now that I look back. Thanks!

hartnn (hartnn):

good work! welcome ^_^

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