Let y = f(x) be a function with domain D = [−6, 10] and range R = [−8, 12]. Find the domain D and range R for each function. Assume f(6) = 12 and f(10) = −8. (Enter your answers using interval notation.) a) y = −2f(x) b) y = |f(x)| c) y = f(x + 2) − 3
for the first one, the domain doesn't change, since it is still \(f(x)\) but the range will change because you will multiply all your outputs by \(-2\) and so the range will be \([-24,16]\)
second one, again the domain doesn't change, but all the outputs will now be positive, so the range will be \([0,12]\)
for the third one, since the smallest number you can use is \(-6\) as an input, we can solve \(x+2=-6\) so get \(x=-8\) largest is 10 solving \(x+2=10\) gives \(x=8\) so the domain of \(f(x+2)-3\) will be \[[-8,10]\] since we are then subtracting 3, range will be \([-11,9]\)
for c [-8,10] did not work
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