Solve the equation by completing the square. 2x^2 + 9x + 1 = 0 x = (smaller value) x = (larger value)
ok... start by dividing each term by 2... what do you get..?
x+9/2+1/2=0
its is undefine?
not quite its \[x^2 + 4.5 x + 0.5 = 0\] next subtract 0.5 from both sides...what do you get..?
x^2 + 4.5 = 0.5
a perfect square when expanded is \[(a + b)^2 = a^2 + 2ab + b^2\]
not quite its \[x^2 + 4.5x = -0.5\] does that make sense?
iy eoulf look like x^2+4.5x+b2 = -0.5?
it would*
if you are working in fraction the equation is \[x^2 + \frac{9x}{2} = - \frac{1}{2}\]
yes... so you need to find 4.5/2 =
2.25
ok... to complete the square you now need to add (2.25)^2 to both sides...
x^2 + 4.5 + 225 = - 0.5 +225
2.25 i mean
so that you will have \[(x + 2.25)^2 = -0.5 + (2.25)^2\]
so the next step is \[(x + 2.25)^2 = 4.5625\] you just need to solve for x...
square root?
to take out the power of 2
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