Question

:::::::::::::::::::::::::::: c program ::::::::::::::::::::::::::
#include void main() { char ch=90; printf("%c",(char*)ch); } what would be the output & why ?

Answer 1

output is "Z".

90 is Ascii value of "Z"(caps Z).

Answer 2

Hope you got the answer.

Answer 3

what is your expected output?

Answer 4

i want to know why this is happening ???

Answer 5

because you are defining %C .
printf("%c",(char*)ch); OUTPUT WILL BE "Z"
printf("%d",(char*)ch); OUTPUT will be "99"

Answer 6

when char ch=90 executes then what gets stored in ch ?

Answer 7

90

Answer 8

and when printf("%c",(char*)ch); executes then what happens ?

Answer 9

It prints it as character. because %c is indication of char value.

Answer 10

Got the answer?