any 2 points determine a line. If there are 6 points in a plane, no 3 of which lie on the same line, how many lines are determined by pairs of these 6 points?
tips?
micah?
Let there be points A, B, C, D, E and F. For point A, there are 5 possible lines (AB, AC, AD, AE, and AF) For point B, there are 4 possible lines (BC, BD, BE, and BF) Keep in mind that AB is excluded since lines AB and BC are considered the same line. For point C, there are 3 possible lines (CD, CE, and CF) (CA and CB excluded) For point D, there are 2 possible lines (DE and DF) (DA, DB, and DC excluded) For point E, there is 1 possible line (EF) (EA, EB, EC, and ED excluded) For point F, there is no possible line. (FA, FB, FC, FD, and FE excluded) 5 + 4 + 3 + 2 + 1 = 15 possible lines.
Does this help?
heck yeah
next problem?
Sure.
Glad I helped.
ty
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